q=%28%E8%8B%B1%29%E9%87%91-%E5%B0%9A%E5%85%8B%E5%B0%94%E6%9B%BC%28Kung-Shankleman&searchType=standard&isFacet=true&view=standard&searchWay=author&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
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(英)金-尚克尔曼(Kung-Shankleman